n^2-16n-75=0

Solution for n^2-16n-75=0 equation:

n^2-16n-75=0

a = 1; b = -16; c = -75;
Δ = b2-4ac
Δ = -162-4·1·(-75)
Δ = 556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{556}=\sqrt{4*139}=\sqrt{4}*\sqrt{139}=2\sqrt{139}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{139}}{2*1}=\frac{16-2\sqrt{139}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{139}}{2*1}=\frac{16+2\sqrt{139}}{2}
$